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4^3+4x^2=x+1
We move all terms to the left:
4^3+4x^2-(x+1)=0
We add all the numbers together, and all the variables
4x^2-(x+1)+64=0
We get rid of parentheses
4x^2-x-1+64=0
We add all the numbers together, and all the variables
4x^2-1x+63=0
a = 4; b = -1; c = +63;
Δ = b2-4ac
Δ = -12-4·4·63
Δ = -1007
Delta is less than zero, so there is no solution for the equation
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